Question

Два резистора сопротивлением в 180 и 30 Ом включены параллельно. В каком из резисторов сила тока больше и во сколько раз?

Answer 1

При параллельном соединении напряжение одинаково
$U= I_1*R_1=I_2*R_2 \\ \frac{I_2}{I_1}= \frac{R_1}{R_2} \\ \frac{I_2}{I_1}=180:30=6$
Чем больше сопротивление, тем меньше ток.
На резисторе 30 Ом сила тока в 6 раз больше.

Answer 2

Calculating Current in Parallel Resistors

When two resistors are connected in parallel, the total current flowing through the circuit is divided between them. To determine in which resistor the current is greater and by how much, we can use the formula:

I = V / R

Where: - I = current - V = voltage - R = resistance

Let's calculate the current flowing through each resistor.

Current Calculation

Using the given resistances: - Resistor 1: 180 Ohms - Resistor 2: 30 Ohms

We can assume a voltage of 1 Volt for simplicity.

The current through each resistor can be calculated using the formula I = V / R:

- For Resistor 1: I1 = 1 / 180 - For Resistor 2: I2 = 1 / 30

Current Comparison

Comparing the currents: - I1 = 1 / 180 - I2 = 1 / 30

We can compare the values to determine in which resistor the current is greater and by how much.

Conclusion

Based on the calculations, the current through Resistor 2 (30 Ohms) is greater than the current through Resistor 1 (180 Ohms). The current through Resistor 2 is 6 times greater than the current through Resistor 1.

This information is based on the calculations using the given resistances and a voltage of 1 Volt.