Question

Пожалуйста решите задачу по физике,надо очень подробно всё объяснить каждое решение, очень срочно!Пожалуйста!Задача:Какое количество энергии выделит вода массой 2 кг при охлаждении от100 до 0 градуса Цельсия?Какое количество энергии выделится,если вместо воды взять столько же пара при 100 градуса цельсия?Главное подробно объяснить !

Answer 1

Qводы=c*m*t=4200*2*100=840000 Дж
Qпара=L*t+c*m*t=23*100000*2+840000=5440000 Дж

Answer 2

Q = mcΔT = 2 * 4200 * 100 = 840000 Дж = 840 кДж.

Q = mr + mcΔT = 2*2300000 + 2*4200*100 = 5440000 Дж = 5,44 МДж.

Answer 3

Problem Analysis

To solve this problem, we need to calculate the amount of energy released when water with a mass of 2 kg is cooled from 100 degrees Celsius to 0 degrees Celsius. We also need to calculate the amount of energy released when the same mass of steam at 100 degrees Celsius is cooled to water at 100 degrees Celsius.

Solution

To calculate the amount of energy released during cooling, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of energy released or absorbed (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Calculation for Water

For water, the specific heat capacity (c) is approximately 4186 J/kg°C The mass (m) is given as 2 kg. The change in temperature (ΔT) is 100°C (initial temperature of 100°C minus final temperature of 0°C).

Plugging these values into the formula, we get:

Q = 2 kg * 4186 J/kg°C * 100°C = 837,200 J

Therefore, the amount of energy released when water with a mass of 2 kg is cooled from 100 degrees Celsius to 0 degrees Celsius is 837,200 joules.

Calculation for Steam

To calculate the amount of energy released when steam is cooled to water at 100 degrees Celsius, we need to consider two steps: 1. Condensing the steam into water at 100 degrees Celsius. 2. Cooling the water from 100 degrees Celsius to 0 degrees Celsius.

Step 1: Condensing Steam to Water at 100°C To condense steam into water at 100 degrees Celsius, we need to consider the latent heat of vaporization. The latent heat of vaporization for water is approximately 2,260,000 J/kg.

Using the mass of 2 kg, we can calculate the energy released during condensation:

Q1 = 2 kg * 2,260,000 J/kg = 4,520,000 J

Step 2: Cooling Water from 100°C to 0°C We can use the same formula as before, with the specific heat capacity of water (c) as 4186 J/kg°C, the mass (m) as 2 kg, and the change in temperature (ΔT) as 100°C.

Q2 = 2 kg * 4186 J/kg°C * 100°C = 837,200 J

Therefore, the total amount of energy released when the same mass of steam at 100 degrees Celsius is cooled to water at 100 degrees Celsius is:

Total Q = Q1 + Q2 = 4,520,000 J + 837,200 J = 5,357,200 J

Therefore, the total amount of energy released is 5,357,200 joules.

Summary

- The amount of energy released when water with a mass of 2 kg is cooled from 100 degrees Celsius to 0 degrees Celsius is 837,200 joules. - The amount of energy released when the same mass of steam at 100 degrees Celsius is cooled to water at 100 degrees Celsius is 5,357,200 joules.

I hope this explanation helps! Let me know if you have any further questions.

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