Question

Определите ЭДС индукции на концах крыльев самолёта,имеющих длину 12 м,если скорость его при горизонтальном полёте 250 м/с,а вертикальная составляющая магнитной индукции земного магнитизма 5,0*10 в -5 степени Тл

Answer 1

e= VBL = 250*5*10^-5*12=15*10^-2   B

Answer 2

Calculation of the Induced EMF on the Ends of the Airplane Wings

To calculate the induced electromotive force (EMF) on the ends of the airplane wings, we need to consider the length of the wings, the velocity of the airplane during horizontal flight, and the vertical component of the Earth's magnetic field.

Given: - Length of the wings (l): 12 m - Velocity of the airplane during horizontal flight (v): 250 m/s - Vertical component of the Earth's magnetic field (B): 5.0 * 10^-5 T

The formula to calculate the induced EMF is:

EMF = B * l * v

Substituting the given values into the formula, we get:

EMF = (5.0 * 10^-5 T) * (12 m) * (250 m/s)

Calculating the result:

EMF = 5.0 * 10^-5 * 12 * 250 = 0.15 V

Therefore, the induced EMF on the ends of the airplane wings is 0.15 volts.