Question

автопогрузчик поднимает груз массой 400 кг на высоту 1,2 м за 2 с. Вычислить совершенную работу и мощность автопогрузчика

Answer 1

Дано:

m=400кг

h=1,2м

t=2с

А-?Дж

N-?Bт

решение:

Работу вычисляем по формуле, что и потенциальная энергия: А=mgh=400кг*10м/с2*1.2м=4800Дж

Мощность по формуле: N=A/t=4800Дж/2с=2400Bт

так наверное!!!

Answer 2

P = A / t

A = mgh

где, Р - мощность, А - работа, m - масса, h - высота, g - ускорение свободного падения

А = 400 * 10 * 1,2 = 4800 Дж

Р = 4800 / 2 = 2400 Вт

Answer 3

Calculating Work and Power of the Forklift

To calculate the work done by the forklift in lifting a 400 kg load to a height of 1.2 m in 2 seconds, we can use the formula for work:

Work (W) = Force (F) × Distance (d)

In this case, the force is the weight of the load (400 kg) multiplied by the acceleration due to gravity (9.81 m/s^2), and the distance is the height the load is lifted (1.2 m).

Using this information, we can calculate the work done by the forklift.

Work (W) = Force (F) × Distance (d) Work (W) = (400 kg × 9.81 m/s^2) × 1.2 m Work (W) = 4708.8 joules

So, the work done by the forklift in lifting the load is 4708.8 joules.

Now, to calculate the power of the forklift, we can use the formula for power:

Power (P) = Work (W) / Time (t)

In this case, the work done is 4708.8 joules, and the time taken is 2 seconds.

Power (P) = 4708.8 joules / 2 seconds Power (P) = 2354.4 watts

So, the power of the forklift is 2354.4 watts.

Therefore, the work done by the forklift in lifting the load is 4708.8 joules, and the power of the forklift is 2354.4 watts.