Question

1м(в кубе) воздуха при 0*С находится в цилиндре под давлением 200кПа.Какая работа будет совершенна при изобарном нагревании на 10*С ?

Answer 1

Воспользуемся законом Гей-Люссака:

v1/t1=v2/t2

выразим v2=t2*V1/T1

Подставляем данные в формулу и получаем:

v2 = 1,037 м^3

A=p * изменение v= 200 000 * 0,037=7400 Дж

Ответ: 7400 Дж.

Answer 2

Problem Statement

A volume of 1 m³ of air at 0°C is contained in a cylinder under a pressure of 200 kPa. What work will be done during an isobaric heating of 10°C?

Solution

To find the work done during an isobaric heating process, we can use the formula:

Work = Pressure * Change in Volume

In this case, the volume remains constant, so the change in volume is zero. Therefore, the work done during the isobaric heating process will be zero.

Answer

The work done during the isobaric heating of 10°C will be zero.

Explanation

During an isobaric process, the pressure remains constant while the volume changes. However, in this case, the volume remains constant at 1 m³. Therefore, there is no change in volume, and as a result, no work is done during the isobaric heating process.

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