Question

При поднятии груза весом 260H с помощью подвижного блока на верёвку действовали с силой 136H. M блока 6H Вычислите КПД установки, если груз требуется поднять на высоту 5 метров

Answer 1

S движения верёвки = 5*2 =10 метров т.к проигрыш в расстоянии в 2 раза.
A1=260Н*5м=1300дж полезная работа
A2=(136Н+6/2Н)*10=1390дж совершённая работа
КПД=А1/А2=1300/1390=93,52%

Answer 2

Calculation of Efficiency (КПД) for Lifting a Load

To calculate the efficiency (КПД) of lifting a load using a movable block and rope, we need to consider the work done and the input energy.

The efficiency (КПД) is given by the formula:

КПД = (Work output / Input energy) * 100%

Calculation of Work Output

The work output is the work done in lifting the load to a certain height. It can be calculated using the formula:

Work output = Force * Distance

In this case, the force applied is the force exerted by the movable block on the rope, which is 136H. The distance is the height to which the load is lifted, which is 5 meters.

Therefore, the work output can be calculated as:

Work output = 136H * 5m = 680 Joules

Calculation of Input Energy

The input energy is the energy supplied to the system to perform the work. In this case, the input energy is the work done by the block, which is the force applied by the block multiplied by the distance the block moves.

The force applied by the block is 136H, and the distance the block moves is the same as the distance the load is lifted, which is 5 meters.

Therefore, the input energy can be calculated as:

Input energy = Force * Distance = 136H * 5m = 680 Joules

Calculation of Efficiency (КПД)

Now that we have the work output and the input energy, we can calculate the efficiency (КПД) using the formula mentioned earlier:

КПД = (Work output / Input energy) * 100%

Substituting the values, we get:

КПД = (680 Joules / 680 Joules) * 100% = 100%

Therefore, the efficiency (КПД) of the lifting system is 100%.

Please note that the efficiency is expressed as a percentage and represents the ratio of the work output to the input energy. In this case, since the work output and the input energy are equal, the efficiency is 100%, indicating that the system is operating at maximum efficiency.

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