Question

Стрела массой 50 г выпущена из лука со скоростью 30м/с вертикально вверх. Каковы значения потенциальной и кинетической энергии стреляя через 2 секунды?

Answer 1

cvjnh

cvсмотри на фото...................................................................................

Answer 2

Дано:

m=50г=0,05кг

V=30м/с

t=2с

Eп-?Дж

Ек-?Дж

решение:

Найдем высоту: h=V/t=30м/с/2с=15м;

Найдем потенциальную энергию: Еп=mgh=0,05кг*10м/с2*15м=7,5Дж.

Найдем кинетическую энергию: Eк=mV^2/2=0,05кг(30м/с2)^2/2=22,5Дж.

так наверное!!!

Answer 3

Given Data

- Mass of the arrow (m) = 50 g = 0.05 kg - Initial velocity of the arrow (v) = 30 m/s - Time elapsed (t) = 2 seconds

Potential and Kinetic Energy

The potential energy (PE) and kinetic energy (KE) of the arrow can be calculated using the following formulas:

1. Potential Energy (PE) = mgh, where: - m = mass of the arrow - g = acceleration due to gravity (approximately 9.81 m/s^2) - h = height

2. Kinetic Energy (KE) = 0.5mv^2, where: - m = mass of the arrow - v = velocity of the arrow

Calculations

First, let's calculate the potential energy (PE) and kinetic energy (KE) of the arrow after 2 seconds.

1. Potential Energy (PE): - Using the formula PE = mgh, where h is the height reached by the arrow.

2. Kinetic Energy (KE): - Using the formula KE = 0.5mv^2, where v is the velocity of the arrow.

Results

Potential Energy (PE): - The potential energy of the arrow after 2 seconds can be calculated using the formula PE = mgh.

Kinetic Energy (KE): - The kinetic energy of the arrow after 2 seconds can be calculated using the formula KE = 0.5mv^2.

Let's calculate the potential and kinetic energy of the arrow after 2 seconds.