
2 однакові заряди розміщені в олії (Е=2). на відстані 3 см , взаємодіють із силою 8 мН ( мілі
ньютона) . оформите пожалуйста полностью с дано...

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Calculation of Electric Field Strength
To answer your question, we need to calculate the electric field strength between two identical charges placed in oil. The charges have a magnitude of 2 units and are separated by a distance of 3 cm. The interaction between them is described by a force of 8 mN (millinewtons).The electric field strength (E) between two charges can be calculated using Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for electric field strength is given by:
E = F / q
Where: - E is the electric field strength - F is the force between the charges - q is the magnitude of the charge
In this case, the force (F) is given as 8 mN and the magnitude of the charge (q) is 2 units. We can substitute these values into the formula to calculate the electric field strength.
E = (8 mN) / (2 units)
To proceed with the calculation, we need to convert millinewtons to newtons. Since 1 N = 1000 mN, we have:
E = (8 × 10^-3 N) / (2 units)
Now, we can calculate the electric field strength:
E = 4 × 10^-3 N / units
Therefore, the electric field strength between the two charges in oil is 4 × 10^-3 N / units.
Please note that the units for electric field strength are newtons per unit charge (N/C) or volts per meter (V/m). However, since the question does not specify the units for the charge, we cannot provide a specific unit for the electric field strength.


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