Question

При какой температуре находился газ в закрытом сосуде, если при его нагревании на T = 300 К давление возросло в 1,5 раза?

Answer 1

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Answer 2

Gas Temperature Calculation

To calculate the initial temperature of the gas in the closed vessel, given that its pressure increased by 1.5 times when heated to T = 300 K, we can use the relationship between pressure and temperature for an ideal gas.

According to the ideal gas law, the relationship between pressure (P), volume (V), and temperature (T) of a gas is given by the equation: P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

Given that the pressure increased by 1.5 times when the temperature was raised to 300 K, we can use the ideal gas law to find the initial temperature.

Using the ideal gas law equation P1/T1 = P2/T2, where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature, we can solve for T1.

We have: - P1 = initial pressure - T1 = initial temperature - P2 = 1.5 * P1 (pressure increased by 1.5 times) - T2 = 300 K (final temperature)

Substituting these values into the ideal gas law equation, we get: P1/T1 = (1.5 * P1)/300

Solving for T1: T1 = (P1 * 300) / (1.5 * P1)

Now, let's calculate the initial temperature using the given values.

T1 = (P1 * 300) / (1.5 * P1)

Using the given values, we have: T1 = (P1 * 300) / (1.5 * P1)

Calculation

T1 = 200 K

Therefore, the initial temperature of the gas in the closed vessel was 200 K.

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