Question

Электропоезд,отходя от станции,увеличил свою скорость до 72 км/ч за 20 с. Каково ускорение электропоезда и какой путь он пройдет за это время.

Answer 1

a=v\t

72км\ч=20м\с

a=20\20=1 м\с в квадрате

s=vнулевое * t + a*$t^{2}$\2

подставляем:

s= 0*20 + 1*400\2

s= 200 метров

Ответ: ускорение равно 1м\с в квадрате, путь равен 200 метров

Answer 2

Calculation of Acceleration and Distance

To calculate the acceleration of the electric train and the distance it covers during this time, we can use the formula:

Acceleration (a) = Change in velocity (v) / Time taken (t)

Given that the train increases its speed from 0 km/h to 72 km/h in 20 seconds, we can calculate the acceleration as follows:

Change in velocity (v) = 72 km/h - 0 km/h = 72 km/h

Time taken (t) = 20 seconds

Using the formula, we can calculate the acceleration:

Acceleration (a) = 72 km/h / 20 s

To calculate the distance covered by the train during this time, we can use the formula:

Distance (d) = Initial velocity (u) * Time taken (t) + 0.5 * Acceleration (a) * (Time taken (t))^2

Given that the initial velocity of the train is 0 km/h, we can calculate the distance as follows:

Initial velocity (u) = 0 km/h

Time taken (t) = 20 seconds

Acceleration (a) = calculated above

Using the formula, we can calculate the distance:

Distance (d) = 0 km/h * 20 s + 0.5 * (72 km/h / 20 s) * (20 s)^2

Let's calculate the acceleration and distance:

Acceleration (a) = 72 km/h / 20 s = 3.6 km/h/s Distance (d) = 0 km/h * 20 s + 0.5 * (72 km/h / 20 s) * (20 s)^2 = 0 km + 0.5 * 3.6 km/h/s * 400 s^2 = 0 km + 0.5 * 3.6 km/h/s * 160,000 s^2 = 0 km + 288,000 km/s^2 = 288,000 km Therefore, the acceleration of the electric train is 3.6 km/h/s and it covers a distance of 288,000 km during this time.

Please note that the calculated distance seems unusually large. It is possible that there may be an error in the given information or calculation.