Question

Работа электрона с поверхности цезия равна 1.9эВ. Определите красную границу фотоэффекта для цезия.

Answer 1

Решение. Lk=(h*c)/A; h=6,625*10^-34; c=3*10^8; A=1,9*1,6*10^-19;

Answer 2

Red Limit of the Photoelectric Effect for Cesium

The work function of cesium, which is the minimum energy needed to remove an electron from the surface of cesium, is given as 1.9 eV. To determine the red limit of the photoelectric effect for cesium, we can use the equation:

Red Limit = Work Function + Energy of the Photon

The energy of a photon can be calculated using the equation:

Energy of Photon = Planck's constant × Frequency

Given that the red light has a wavelength of approximately 700 nm, we can calculate the frequency using the speed of light equation:

Frequency = Speed of Light / Wavelength

Substituting the values, we get:

Frequency = (3.00 × 10^8 m/s) / (700 × 10^-9 m)

Calculating the frequency and then the energy of the photon, we can then determine the red limit of the photoelectric effect for cesium.