
Мяч бросили вертикально вверх со скоростью 15 м/с. Если пренебречь силой сопротивления воздуха то
через 1 с мяч окажется на высоте

Ответы на вопрос




Calculation of the height of the ball after 1 second
To calculate the height of the ball after 1 second, we can use the equations of motion. Since we are neglecting air resistance, the only force acting on the ball is gravity.
The equation that relates the initial velocity, time, and height of an object in free fall is:
h = h0 + v0t - (1/2)gt^2
Where: - h is the final height of the ball - h0 is the initial height of the ball (which is not given in the question) - v0 is the initial velocity of the ball (15 m/s) - t is the time (1 second) - g is the acceleration due to gravity (approximately 9.8 m/s^2)
Since the initial height is not given in the question, we cannot calculate the exact height of the ball after 1 second. We would need to know the initial height to determine the final height accurately.
However, if we assume that the ball was thrown from the ground (h0 = 0), we can calculate the height using the equation:
h = v0t - (1/2)gt^2
Substituting the given values: - v0 = 15 m/s - t = 1 second - g = 9.8 m/s^2
We can calculate the height of the ball after 1 second:
h = (15 m/s)(1 s) - (1/2)(9.8 m/s^2)(1 s)^2
Simplifying the equation, we get:
h = 15 m - 4.9 m
Therefore, if we neglect air resistance and assume the ball was thrown from the ground, the ball would be at a height of approximately 10.1 meters after 1 second.
Please note that this calculation assumes ideal conditions and neglects factors such as air resistance and the initial height of the ball. The actual height of the ball after 1 second may vary depending on these factors.
Conclusion
If we neglect air resistance and assume the ball was thrown from the ground, the ball would be at a height of approximately 10.1 meters after 1 second. However, please note that this calculation is based on certain assumptions and may not accurately represent real-world conditions.


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