Question

Вода при температуре 20°C превращается в пар. Масса воды - 100г, t1 - 10°СНайти количество теплоты.

Answer 1

Дано: 
m = 100г  (СИ - 0.1кг)
t1=10C°
t2=20C°
C=4200Дж/кг*°С
Найти: Q-? 
Решение: Q=cm(t2-t1) 
Q=  4200*0.1(20-10)=420*10=4200Дж

Answer 2

Calculation of Heat Quantity

To find the quantity of heat required to convert 100g of water at 10°C to steam at 20°C, we can use the formula:

Q = mcΔT

Where: - Q is the quantity of heat - m is the mass of the substance (in this case, water) in grams - c is the specific heat capacity of the substance - ΔT is the change in temperature

In this case, the mass of water is 100g, the initial temperature (t1) is 10°C, and the final temperature (t2) is 20°C.

Now, let's find the specific heat capacity of water and calculate the quantity of heat required.

Specific Heat Capacity of Water

The specific heat capacity of water is approximately 4.18 J/g°C This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

Calculation

Using the formula Q = mcΔT, we can calculate the quantity of heat required to convert 100g of water at 10°C to steam at 20°C.

Q = (100g) * (4.18 J/g°C) * (20°C - 10°C)

Simplifying the equation:

Q = 100g * 4.18 J/g°C * 10°C

Q = 4180 J

Therefore, the quantity of heat required to convert 100g of water at 10°C to steam at 20°C is 4180 Joules.

Please note that this calculation assumes that the water is at atmospheric pressure and that no heat is lost to the surroundings during the process.

I hope this helps! Let me know if you have any further questions.