Question

Активное сопротивление проводника равно 15 ом, а его индуктивность 0,063 гн. определите полное сопротивление проводника в сети переменного тока частотой 50 гц а- 5 ом б - 15 ом в- 20 ом г- 25 ом д - 50 ом

Answer 1

Полное сопротивление равно Z=√(R²+(2*π*f*L)³)=√(15²+(2*π*50*0,063)²)=24,826 Ом≈25 Ом.

Ответ: а)

Answer 2

Calculation of Total Resistance

To determine the total resistance of the conductor in an AC circuit with a frequency of 50 Hz, we need to consider both the resistance and inductance of the conductor.

Given: - Active resistance of the conductor = 15 Ω - Inductance of the conductor = 0.063 H

The total impedance of the conductor in an AC circuit can be calculated using the formula:

Z = √(R^2 + (ωL)^2)

Where: - Z is the total impedance - R is the resistance - ω is the angular frequency (2πf, where f is the frequency) - L is the inductance

In this case, the angular frequency ω can be calculated as:

ω = 2πf = 2π * 50 Hz = 100π rad/s

Now, let's calculate the total impedance:

Z = √(15^2 + (100π * 0.063)^2)

Calculating this expression gives us the total impedance Z.

Please note that the question asks for the total resistance, not impedance. To find the total resistance, we need to take the real part of the impedance.

Calculation of Total Resistance

To calculate the total resistance, we need to take the real part of the impedance. The real part of the impedance is equal to the resistance.

Therefore, the total resistance of the conductor in the AC circuit is 15 Ω (option a).