Question

В сосуд налиты две жидкости вода и ртуть. Высота столба ртути 20 см. Какова высота столба воды, если жидкости оказывают давление на дно 1,2 МПа

Answer 1

H = p / po * g 

p - давление ( 1,2 МПа = 1200000 Па ) 
po - плотность ( для воды 1000 кг / м³ ) 
g - ускорение свободного падения ( 10 Н / кг ) 

h = 1200000 / 1000 * 10 = 1200000 / 10000 = 120 см 

Answer 2

Calculating the Height of the Water Column

To calculate the height of the water column in the vessel, we can use the principles of hydrostatics and the given pressure exerted by the two liquids.

The pressure exerted by a liquid at a certain depth is given by the equation:

P = ρgh

Where: - P = pressure - ρ = density of the liquid - g = acceleration due to gravity - h = height of the liquid column

Given: - Pressure exerted by the liquids on the bottom = 1.2 MPa - Height of the mercury column = 20 cm

We can use the equation P = ρgh to find the height of the water column.

Calculation

First, let's find the density of mercury and water.

The density of mercury is approximately 13,600 kg/m³. The density of water is approximately 1,000 kg/m³.

Using the given pressure and the density of mercury, we can calculate the height of the mercury column using the equation P = ρgh.

1. For Mercury: 1.2 MPa = (13,600 kg/m³) * (9.81 m/s²) * h h = (1.2 * 10⁶ Pa) / (13,600 kg/m³ * 9.81 m/s²) h ≈ 0.0088 m h ≈ 8.8 cm

Now, we can calculate the height of the water column using the same equation.

2. For Water: 1.2 MPa = (1,000 kg/m³) * (9.81 m/s²) * h h = (1.2 * 10⁶ Pa) / (1,000 kg/m³ * 9.81 m/s²) h ≈ 122.1 m h ≈ 122.1 cm

Conclusion

The height of the water column in the vessel is approximately 122.1 cm.