Question

До какой температуры нагреется газовая смесь в цилиндре двигателя внутреннего сгорания, если в результате сжатия объём уменьшился в 8 раз, а давление возросло до 1,52 МПа? До сжатия газовая смесь имела температуру 50°С при нормальном атмосферном давлении.

Answer 1

Здесь можно решать задачу по обобщенному газовому закону:
p₀*V₀/T₀ = p*V/T

p₀=1*10⁵ Па
p = 15,2*10⁵ Па
V
V₀=8*V
T₀=50+273=323 К
_______________
T - ?

T = p*V*T₀ / (p₀*V₀) = 15,2*V*323 / (1*8*V) = 15,2*323/8 ≈ 614 К
t = T-273 = 614-273 = 341°C

Answer 2

Calculation of the Final Temperature

To calculate the final temperature of the gas mixture in the cylinder of an internal combustion engine, we can use the ideal gas law equation:

P1V1/T1 = P2V2/T2

Where: - P1 is the initial pressure of the gas mixture - V1 is the initial volume of the gas mixture - T1 is the initial temperature of the gas mixture - P2 is the final pressure of the gas mixture - V2 is the final volume of the gas mixture - T2 is the final temperature of the gas mixture

In this case, we are given the following information: - The initial temperature of the gas mixture (T1) is 50°C. - The initial volume of the gas mixture (V1) is not provided. - The final volume of the gas mixture (V2) is 1/8 times the initial volume (V1). - The final pressure of the gas mixture (P2) is 1.52 MPa.

To solve for the final temperature (T2), we need to find the initial volume (V1). Unfortunately, the initial volume is not provided in the question. Therefore, we cannot calculate the final temperature without this information.

Please provide the initial volume of the gas mixture so that we can proceed with the calculation.