Question

Определите электроёмкость конденсатора, для изготовления которого использовали ленту алюминиевой фольги длинной 150см и шириной 90мм.

Answer 1

Дано:
а=150 см=1,5 м 
b=90 мм=0,09 м 
E=2
Eo=8,85*10^-12 Ф/м 
d=10^-4 м  
Решение: 
S=a*b=1,5*0,09=0,135 м^2
С=(E*Eo*S)/d=(2*8,85*10^-12*0,135)/10^-4=2,98*10^-8 Ф=29,8 нФ

Answer 2

Calculating the Capacitance of a Capacitor Made from Aluminum Foil

To determine the capacitance of a capacitor made from aluminum foil, we need to know the dimensions of the foil and the dielectric material used. In this case, we are given that the aluminum foil has a length of 150 cm and a width of 90 mm.

The formula to calculate the capacitance of a parallel plate capacitor is:

C = (ε₀ * εᵣ * A) / d

Where: - C is the capacitance of the capacitor, - ε₀ is the permittivity of free space (approximately 8.854 x 10⁻¹² F/m), - εᵣ is the relative permittivity (also known as the dielectric constant) of the material between the plates, - A is the area of the plates, and - d is the distance between the plates.

In this case, the aluminum foil acts as one of the plates, and the air (or vacuum) between the plates acts as the dielectric material. The relative permittivity of air is very close to 1, so we can approximate it as such.

To calculate the area of the plates, we need to convert the dimensions to meters. The length of the foil is 150 cm, which is equal to 1.5 meters. The width of the foil is 90 mm, which is equal to 0.09 meters.

Area (A) = length * width = 1.5 m * 0.09 m = 0.135 square meters

Now, we can substitute the values into the formula to calculate the capacitance:

C = (8.854 x 10⁻¹² F/m * 1 * 0.135 m²) / d

Unfortunately, we don't have the information about the distance between the plates (d). Without this information, we cannot calculate the capacitance accurately. If you have the value of d, please provide it, and I will be happy to help you calculate the capacitance.

Please note that the values provided in the search snippets are not directly related to the given question and do not provide the necessary information to calculate the capacitance of the capacitor made from aluminum foil.