Question

Какое количество теплоты необходимо для нагревания воды в бассейне длиной 100 м, шириной 6 м и глубиной 2 м температурой 16 °С до температуры 25 °С (св = 4200 дж/кг⋅°С, Pв = 1000 кг/м³)?

Answer 1

Найдём объём бассейна V=abc  V=100*6*2=1200м3    Найдём массу воды  m=vρ    m=1200*1000=1200000кг      Найдём количество теплоты Q=cm(t₂-t₁)  Q=4200*1200000*9=45360000000Дж=45360МДж

Answer 2

Calculation of Heat Required to Heat the Pool

To calculate the amount of heat required to heat the pool, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy required (in joules) - m is the mass of water (in kilograms) - c is the specific heat capacity of water (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given the dimensions of the pool and the specific heat capacity of water, we can calculate the mass of water in the pool and then use the formula to find the heat energy required.

Calculation Steps

1. Calculate the volume of the pool: - Length = 100 m - Width = 6 m - Depth = 2 m

Volume = Length * Width * Depth

2. Calculate the mass of water in the pool: - Density of water (Pв) = 1000 kg/m³

Mass = Volume * Density

3. Calculate the change in temperature: - Initial temperature = 16 °C - Final temperature = 25 °C

ΔT = Final temperature - Initial temperature

4. Calculate the heat energy required: - Specific heat capacity of water (св) = 4200 J/kg⋅°C

Q = Mass * Specific heat capacity * ΔT

Let's perform the calculations.

Calculation Results

1. Volume of the pool: - Length = 100 m - Width = 6 m - Depth = 2 m

Volume = 100 m * 6 m * 2 m = 1200 m³

2. Mass of water in the pool: - Density of water (Pв) = 1000 kg/m³

Mass = Volume * Density = 1200 m³ * 1000 kg/m³ = 1,200,000 kg

3. Change in temperature: - Initial temperature = 16 °C - Final temperature = 25 °C

ΔT = Final temperature - Initial temperature = 25 °C - 16 °C = 9 °C

4. Heat energy required: - Specific heat capacity of water (св) = 4200 J/kg⋅°C

Q = Mass * Specific heat capacity * ΔT = 1,200,000 kg * 4200 J/kg⋅°C * 9 °C = 45,360,000,000 J

Therefore, the amount of heat required to heat the pool from 16 °C to 25 °C is 45,360,000,000 joules.

Please note that the above calculations assume that there are no heat losses to the surroundings during the heating process.