Question

Расстояние между городом и деревней 40000 м. первую половину этого пути автомобилист проехал со скоростью 22 м.с, а второю 11 м.с. Чему равна средняя скорость его движения?заранее спасибо!

Answer 1

1) 20000 : 22 =  909, 1 м/сек
2) 20000 : 11 =  1818,2 м/сек
3) 40000 : (909,2 + 1818,4) = 40000 : 2717,6 = 14,66 - м/сек - средняя скорость автомобилиста

Answer 2

Формула для средней скорости:
$v_{sred}=\frac{S_1+S_2+S_3...}{t_1+t_2+t_3...}$

Первую половину пути он проехал за 20000/22=909 сек
вторую за 20000/11=1818 сек
Средняя скорость равна:
$v=\frac{ 40000}{909+1818 }=14,668133480014668133480014668133$

Ответ: Vсред=14,7 м/с

Answer 3

Calculating Average Speed

To calculate the average speed of the car, we can use the formula:

Average Speed = Total Distance / Total Time

Given: - Distance between the city and the village = 40000 m - Speed for the first half of the distance = 22 m/s - Speed for the second half of the distance = 11 m/s

Let's calculate the average speed using the provided information.

Calculation

The total distance is 40000 m, and the total time can be calculated by adding the time taken for the first half of the distance and the time taken for the second half of the distance.

The time taken for the first half of the distance: ``` Time = Distance / Speed Time = 20000 m / 22 m/s Time = 909.09 s ```

The time taken for the second half of the distance: ``` Time = Distance / Speed Time = 20000 m / 11 m/s Time = 1818.18 s ```

The total time: ``` Total Time = Time for first half + Time for second half Total Time = 909.09 s + 1818.18 s Total Time = 2727.27 s ```

Now, we can calculate the average speed: ``` Average Speed = Total Distance / Total Time Average Speed = 40000 m / 2727.27 s Average Speed ≈ 14.67 m/s ```

The average speed of the car over the entire distance is approximately 14.67 m/s.