Question

тело за 1 мин совершило 300 колебаний.определите период и частоту колебаний

Answer 1

тело за 1 мин совершило 300 колебаний.определите период и частоту колебаний

Answer 2

Дано:                                СИ
t = 1 мин                           60 c
n = 300
___________
T - ?
υ - ?

Период:
T = t / n = 60 / 300 = 0,2 c

Частота колебаний:
υ = 1 / T = 1/0,2 = 5 Гц

Answer 3

Calculation of Period and Frequency of Oscillations

To determine the period and frequency of oscillations, we need to use the formula:

Period (T) = Time (t) / Number of Oscillations (n)

Given that the body completes 300 oscillations in 1 minute (60 seconds), we can calculate the period as follows:

T = t / n = 60 / 300 = 0.2 seconds.

The period represents the time taken for one complete oscillation.

To calculate the frequency, we can use the formula:

Frequency (f) = 1 / Period (T)

Substituting the value of the period we calculated earlier, we get:

f = 1 / T = 1 / 0.2 = 5 Hz.

The frequency represents the number of oscillations per second.

Therefore, the period of the oscillations is 0.2 seconds, and the frequency is 5 Hz.

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