Question

Плечи рычага равны 30 см и 12 см. К большему плечу прикреплён груз массой 0,8 кг. Определите массу второго груза, если рычаг находится в равновесии.

Answer 1

F1*l1=F2*l2

m1*l1=m2*l2

m2=m1*l1/l2

m2=0.8*0.3/0.12=2 (кг)

Answer 2

Solution:

Given: - Length of the longer arm of the lever, l1 = 30 cm - Length of the shorter arm of the lever, l2 = 12 cm - Mass attached to the longer arm, m1 = 0.8 kg

To find: - Mass attached to the shorter arm, m2

Calculation:

Using the principle of moments, we can calculate the mass attached to the shorter arm of the lever.

The formula for the principle of moments is: F1/F2 = l2/l1

Where: - F1 is the force acting on the longer arm - F2 is the force acting on the shorter arm - l1 is the length of the longer arm - l2 is the length of the shorter arm

Rearranging the formula, we get: F1 = F2 * (l2/l1)

Given that F1 = m1 * g (where g is the acceleration due to gravity, approximately 9.8 m/s^2), we can solve for F2: F2 = F1 / (l2/l1)

Substitute the given values: F2 = m1 * g / (l2/l1)

Now, we can calculate the mass attached to the shorter arm, m2: m2 = F2 / g

Substitute the Values:

Using the given values: - m1 = 0.8 kg - g = 9.8 m/s^2 - l1 = 30 cm = 0.3 m - l2 = 12 cm = 0.12 m

We can calculate: F2 = 0.8 * 9.8 / (0.12 / 0.3) m2 = F2 / 9.8

Result:

After the calculation, the mass attached to the shorter arm, m2, is approximately 2.0 kg.