Question

как изменится сила всемирного тяготения если массу одного из взаимодействующих тел уменьшить в 6 раз а расстояние уменьшить в 2 раза?)

Answer 1

F=G*(m1*m2):r^2

уменьшится в 2:3 раза.

вроде так 

Answer 2

Changes in the Force of Gravity

If the mass of one of the interacting bodies is reduced by 6 times and the distance between them is reduced by 2 times, the force of gravity between them will change. To calculate the new force of gravity, we can use the formula:

F = G * (m1 * m2) / r^2 Where: - F is the force of gravity - G is the gravitational constant (approximately 6.674 * 10^-11 Nm^2/kg^2) - m1 and m2 are the masses of the two bodies - r is the distance between the centers of the two bodies

Let's calculate the new force of gravity step by step.

1. Original force of gravity: - Let's assume the original mass of one of the bodies is 50,000 kg and the distance between them is 1,000 meters. - Plugging these values into the formula, we get: F = 6.674 * 10^-11 * (50,000 * 50,000) / (1,000 * 1,000) F ≈ 16,685 N 2. New force of gravity: - If we reduce the mass of one of the bodies by 6 times, the new mass would be 50,000 / 6 = 8,333.33 kg. - If we reduce the distance between them by 2 times, the new distance would be 1,000 / 2 = 500 meters. - Plugging these new values into the formula, we get: F = 6.674 * 10^-11 * (8,333.33 * 50,000) / (500 * 500) F ≈ 1,111.11 N

Therefore, if the mass of one of the interacting bodies is reduced by 6 times and the distance is reduced by 2 times, the force of gravity between them will decrease from approximately 16,685 N to approximately 1,111.11 N.

Please note that these calculations are based on the assumption that the other body's mass remains constant and there are no other external factors affecting the force of gravity.

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