Question

Найдите среднюю кинетическую энергию поступательного движения молекул газа при температуре 300К

Answer 1

Найти среднюю кинетическую энергию поступательного движения молекул газа при температуре 300 К

Е=mv^2/2=3/2*kT=3/2*1.38*10^-23*300=6.21*10^-21 Дж
k=1.38*10^-23 Дж/К- постоянная Больцмана

ОТВЕТ 6.21*10^-21 Дж

Answer 2

Calculation of Average Kinetic Energy of Gas Molecules at 300K

To calculate the average kinetic energy of gas molecules at a temperature of 300K, we can use the formula for kinetic energy:

Kinetic Energy (KE) = (1/2) * m * v^2

Where: - KE is the kinetic energy - m is the mass of the gas molecule - v is the velocity of the gas molecule

To find the average kinetic energy, we need to consider the average velocity of the gas molecules. According to the kinetic theory of gases, the average velocity of gas molecules is related to the temperature by the equation:

Average Velocity (v) = sqrt((8 * k * T) / (π * m))

Where: - k is the Boltzmann constant (1.38 x 10^-23 J/K) - T is the temperature in Kelvin - m is the mass of the gas molecule

Now, let's substitute the values into the equation to calculate the average kinetic energy.

Using the given temperature of 300K, we can calculate the average velocity using the formula above. However, we need to know the mass of the gas molecule to proceed with the calculation. Unfortunately, the search results do not provide the necessary information to determine the mass of the gas molecule.

Therefore, without the specific information about the gas molecule, it is not possible to calculate the average kinetic energy at a temperature of 300K.