Question

определить энергию магнитного поля солиноида, в котором при силе тока 5 А возникает магнитный поток 0.5 Вб

Answer 1

$W=\frac{\Phi I}2$

W=5*0.5*0.5=1.25 J

Answer 2

Calculating the Energy of a Magnetic Field in a Solenoid

To calculate the energy of a magnetic field in a solenoid, we can use the formula:

W = 0.5 * L * I^2

Where: - W is the energy stored in the magnetic field - L is the inductance of the solenoid - I is the current flowing through the solenoid

Given: - Current (I) = 5 A - Magnetic flux (Φ) = 0.5 Wb (we can use this to calculate the inductance)

Calculating the Inductance of the Solenoid

The inductance of the solenoid can be calculated using the formula:

L = Φ / I

Where: - L is the inductance - Φ is the magnetic flux - I is the current

Substitute the given values: L = 0.5 Wb / 5 A = 0.1 H

Calculating the Energy of the Magnetic Field

Now that we have the inductance, we can calculate the energy of the magnetic field using the formula:

W = 0.5 * L * I^2

Substitute the given values: W = 0.5 * 0.1 H * (5 A)^2 = 1.25 J

So, the energy of the magnetic field in the solenoid, when a current of 5 A produces a magnetic flux of 0.5 Wb, is 1.25 joules.