Question

Тело массой 5 кг подняли на высоту 10м под действием постоянной силы.Работа силы тяжести при этом равна ....

Answer 1

А=F*S
F=m*g
A=m*g*S=5*10*10=500(Дж)

Answer 2

Calculation of Work Done by the Force of Gravity

To calculate the work done by the force of gravity when lifting a body of mass 5 kg to a height of 10 m under the action of a constant force, we can use the formula:

Work (W) = force (F) x displacement (d) x cos(theta)

In this case, the force of gravity is acting vertically downwards, and the displacement is vertical as well. Therefore, the angle between the force and displacement is 0 degrees, and cos(theta) = 1.

The force of gravity can be calculated using the formula:

Force (F) = mass (m) x acceleration due to gravity (g)

where the acceleration due to gravity is approximately 9.8 m/s^2.

Let's calculate the work done:

Step 1: Calculate the force of gravity (F): - mass (m) = 5 kg - acceleration due to gravity (g) = 9.8 m/s^2

Using the formula F = m x g, we can calculate the force of gravity: - F = 5 kg x 9.8 m/s^2 = 49 N Step 2: Calculate the work done (W): - force (F) = 49 N - displacement (d) = 10 m - cos(theta) = 1

Using the formula W = F x d x cos(theta), we can calculate the work done: - W = 49 N x 10 m x 1 = 490 J

Therefore, the work done by the force of gravity when lifting a body of mass 5 kg to a height of 10 m is 490 Joules.