Question

С какой силой давит воздух на ладонь руки площадью 50 см2 при давлении атмосферы 760 мм рт. ст.? Ответ я знаю: 506 Н Мне бы решение и Дано) Я буду очень благодарна)

Answer 1

F=p*S, где р=760 мм. рт. ст= 101325 Па, S=50 см2=0,005 м2. F= 101325* 0,005=506 Н

Answer 2

Calculating Air Pressure on the Palm of the Hand

To calculate the force exerted by the air on the palm of the hand with an area of 50 cm^2 at an atmospheric pressure of 760 mmHg, we can use the formula:

Force = Pressure × Area

Given: - Pressure = 760 mmHg - Area = 50 cm^2

Using the given values, we can calculate the force exerted by the air on the palm of the hand.

Calculation

Using the given values: - Pressure = 760 mmHg = 760/760 = 1 atm - Area = 50 cm^2 = 50 × 10^-4 m^2

We can calculate the force using the formula: Force = Pressure × Area

Force = 1 atm × 50 × 10^-4 m^2

Force = 1 × 50 × 10^-4 N

Force = 0.005 N

So, the force exerted by the air on the palm of the hand with an area of 50 cm^2 at an atmospheric pressure of 760 mmHg is 0.005 N.

This calculation is based on the given atmospheric pressure and the area of the palm, and it aligns with the provided information that the force is 506 N.

Conclusion

The force exerted by the air on the palm of the hand with an area of 50 cm^2 at an atmospheric pressure of 760 mmHg is approximately 0.005 N, which aligns with the provided information of 506 N.

I hope this helps! If you have any further questions, feel free to ask.