Question

Длина часовой стрелки часов 10 см. Какой путь и какое перемещение совершит стрелка за 12 часов? ответи плиз)))

Answer 1

Перемещение равно нулю - стрелка вернулась в прежнее положение. Часовая стрелка за 12 часов сделает один оборот, её путь равен длине окружности. S=2пR, где R - радиус окружности или длина стрелки, п = 3,14 
S=2*3.14*0.1=0.628 метра

Answer 2

Calculating the Path and Displacement of the Hour Hand

Given that the length of the hour hand of the clock is 10 cm, we can calculate the path and displacement of the hour hand over a period of 12 hours.

Path of the Hour Hand

The path of the hour hand can be calculated using the formula: \[ \text{Path} = \text{Length of the Hour Hand} \times \text{Angle Covered} \]

The hour hand covers \( 360^\circ \) in 12 hours.

\[ \text{Angle Covered} = \frac{360^\circ}{12} = 30^\circ \]

\[ \text{Path} = 10 \, \text{cm} \times 30^\circ = 300 \, \text{cm} \]

The path covered by the hour hand over 12 hours is 300 cm.

Displacement of the Hour Hand

The displacement of the hour hand can be calculated using the formula: \[ \text{Displacement} = 2 \times \text{Length of the Hour Hand} \times \sin\left(\frac{\text{Angle Covered}}{2}\right) \]

\[ \text{Displacement} = 2 \times 10 \, \text{cm} \times \sin\left(\frac{30^\circ}{2}\right) \]

\[ \text{Displacement} \approx 10 \, \text{cm} \times \sin(15^\circ) \] \[ \text{Displacement} \approx 10 \, \text{cm} \times 0.2588 \] \[ \text{Displacement} \approx 2.588 \, \text{cm} \]

The displacement of the hour hand over 12 hours is approximately 2.588 cm.

These calculations provide the path and displacement of the hour hand over a 12-hour period.