Question

На взлетной полосе длиной 900 м самолет разгоняется до скорости 40 м/с. Какова скорость самолета на расстоянии 225 м от начала полосы?

Answer 1

S=(V²-V₀²)/2a
V₀²=0
a=V₁²/2S₁=1600/1800=0.9 м/с²
V₂=√2S₂a=√2*225*0.9=20 м/с

Answer 2

Calculation of the Speed of the Plane

To calculate the speed of the plane at a distance of 225 m from the start of the runway, we can use the formula for uniform acceleration:

v^2 = u^2 + 2as

Where: - v is the final velocity (the speed of the plane at a distance of 225 m) - u is the initial velocity (the speed of the plane at the start of the runway) - a is the acceleration (which we assume to be constant) - s is the distance traveled (225 m)

Given that the initial velocity (u) is 40 m/s and the distance traveled (s) is 225 m, we can substitute these values into the formula:

v^2 = (40 m/s)^2 + 2 * a * 225 m

Now, we need to find the value of acceleration (a). Unfortunately, the search results did not provide the value of acceleration directly. However, we can make an assumption that the acceleration is constant throughout the entire runway.

Let's assume that the acceleration is 0. We can then calculate the speed of the plane at a distance of 225 m using the formula:

v^2 = (40 m/s)^2 + 2 * 0 * 225 m

Simplifying the equation, we get:

v^2 = (40 m/s)^2

Taking the square root of both sides, we find:

v = 40 m/s

Therefore, the speed of the plane at a distance of 225 m from the start of the runway is 40 m/s.

Please note that this calculation assumes a constant acceleration throughout the entire runway. In reality, the acceleration of an aircraft during takeoff may vary depending on various factors such as aircraft weight, engine power, and air density.