Question

Санки массой 20 кг тянут в гору с постоянной скоростью.Угол наклона к горизонту 60 градусов.Коэффициент трения скольжения по плоскости 0,04 .Определить

Answer 1

F-m*g*sina-k*m*g*cosa=0
F=m*g*(sina+k*cosa)=20*10*(0,87+0,04*0,5)=178 H

Answer 2

Calculation of the Normal Force

To determine the normal force acting on the sled, we need to consider the forces acting on it. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the sled is being pulled uphill at a constant speed, so the normal force will be equal to the weight of the sled.

The weight of the sled can be calculated using the formula:

Weight (W) = mass (m) × acceleration due to gravity (g)

Given that the mass of the sled is 20 kg, we can calculate the weight as follows:

W = 20 kg × 9.8 m/s^2

Calculation of the Frictional Force

The frictional force can be calculated using the formula:

Frictional Force (F) = coefficient of sliding friction (μ) × Normal Force (N)

The coefficient of sliding friction is given as 0.04 We have already calculated the normal force as the weight of the sled. Therefore, we can calculate the frictional force as follows:

F = 0.04 × W

Calculation of the Force Applied

The force applied to pull the sled uphill can be calculated using the formula:

Force Applied (F_applied) = Frictional Force (F) + Weight (W) × sin(θ)

Where θ is the angle of inclination with respect to the horizontal plane. In this case, the angle of inclination is given as 60 degrees Therefore, we can calculate the force applied as follows:

F_applied = F + W × sin(60 degrees)

Calculation of the Net Force

The net force acting on the sled can be calculated using the formula:

Net Force (F_net) = Force Applied (F_applied) - Frictional Force (F)

Therefore, we can calculate the net force as follows:

F_net = F_applied - F

Verification of the Calculations

To verify the calculations, we can substitute the values given in the question into the formulas and calculate the results.

Weight (W) = 20 kg × 9.8 m/s^2 = 196 N

Frictional Force (F) = 0.04 × 196 N = 7.84 N

Force Applied (F_applied) = 7.84 N + 196 N × sin(60 degrees) ≈ 7.84 N + 196 N × 0.866 ≈ 7.84 N + 169.936 N ≈ 177.776 N

Net Force (F_net) = 177.776 N - 7.84 N ≈ 169.936 N

Therefore, the net force acting on the sled is approximately 169.936 N.

Please note that these calculations are based on the given information and assumptions.