Question

Какой тормозной путь пройдет автомобиль ни горизонтальным участке дороги после выключения двиготеля , если коэффицент трения 0,2 ,а начальная скорость движения 72км/ч .

Answer 1

V= 72км/ч = 20 м/с

a=g*k=2м/с^2
S=v^2/2a=20^2/(2*2) м = 100 м

Answer 2

Calculating Braking Distance

To calculate the braking distance of a car on a horizontal road after the engine is turned off, we can use the following formula:

Braking Distance = (Initial Velocity)^2 / (2 * Coefficient of Friction * Acceleration due to Gravity)

Given: - Coefficient of friction (μ) = 0.2 - Initial velocity = 72 km/h

First, we need to convert the initial velocity from km/h to m/s: - 72 km/h = 20 m/s

Now, we can use the formula to calculate the braking distance: - Braking Distance = (20 m/s)^2 / (2 * 0.2 * 9.8 m/s^2)

Calculation

Braking Distance = (20)^2 / (2 * 0.2 * 9.8) Braking Distance = 400 / (3.92) Braking Distance ≈ 102.04 meters

So, the car will travel approximately 102.04 meters before coming to a complete stop after the engine is turned off on a horizontal road.

This calculation is based on the formula for braking distance and the given coefficient of friction and initial velocity