Question

Для накачиванию бензина в бак автомобиля , рабочий заправки использует насос производительностью 20 кг в минуту . Определите время , необходимое для заполнения бака . Если его длина 2 м , ширина 150 см , высота 1800мм. А) 120 мин. Б) 3,6 часа В) 2 часа Г) 1 час

Answer 1

  В) 2 часа  

Answer 2

Calculation of Time Required to Fill the Car Tank

To determine the time required to fill the car tank, we need to calculate the volume of the tank and then divide it by the pumping rate of the fuel pump.

Given: - Pumping rate: 20 kg per minute - Tank dimensions: length = 2 m, width = 150 cm, height = 1800 mm

First, let's convert the dimensions to a consistent unit. Since the pumping rate is given in kilograms, let's convert the dimensions to meters.

- Length: 2 m - Width: 1.5 m (150 cm = 1.5 m) - Height: 1.8 m (1800 mm = 1.8 m)

Next, we calculate the volume of the tank using the formula: volume = length * width * height.

- Volume = 2 m * 1.5 m * 1.8 m = 5.4 cubic meters

Now, we can calculate the time required to fill the tank by dividing the volume of the tank by the pumping rate.

- Time = volume / pumping rate = 5.4 cubic meters / 20 kg per minute

To simplify the calculation, we need to convert the volume from cubic meters to kilograms. Since the density of gasoline is approximately 0.75 kg per liter, we can multiply the volume by the density to get the mass.

- Mass = volume * density = 5.4 cubic meters * 0.75 kg per liter

Now, we can calculate the time required to fill the tank.

- Time = mass / pumping rate = (5.4 cubic meters * 0.75 kg per liter) / 20 kg per minute

Calculating the above expression, we find that the time required to fill the tank is approximately 0.2025 minutes or 12.15 seconds.

Therefore, the correct answer is A) 120 minutes.

Please note that the given search results did not provide specific information about the pumping rate of a fuel pump or the density of gasoline. The calculation above assumes a pumping rate of 20 kg per minute and a gasoline density of 0.75 kg per liter.