Question

На дно бидона с солоком упал алюминиевый черпак . На него действует архимедова сила, равная 2,1Н . Каким стал его вес в молоке, если в воздухе он был равен 5,4 Н?

Answer 1

Fa= Pвозд - Pм⇒  Pм=P возд - Fa=5,4 H -2,1 H=3,3 H

Answer 2

Calculation of the Weight of the Aluminum Ladle in Milk

To calculate the weight of the aluminum ladle in milk, we need to consider the buoyant force acting on it in the milk. The buoyant force is equal to the weight of the fluid displaced by the object. In this case, the fluid is milk.

Given: - Weight of the aluminum ladle in air = 5.4 N - Archimedes' force acting on the ladle = 2.1 N

To find the weight of the ladle in milk, we need to subtract the buoyant force from the weight of the ladle in air.

Let's assume the weight of the ladle in milk is W.

According to Archimedes' principle, the buoyant force is equal to the weight of the fluid displaced by the object. Therefore, the buoyant force acting on the ladle in milk is also equal to 2.1 N.

The weight of the ladle in milk can be calculated using the following equation:

Weight of ladle in air - Buoyant force = Weight of ladle in milk

Substituting the given values:

5.4 N - 2.1 N = W

Simplifying the equation:

3.3 N = W

Therefore, the weight of the aluminum ladle in milk is 3.3 N.

Please note that the provided search results did not provide any relevant information for this specific calculation. However, the calculation is based on the principles of buoyancy and Archimedes' principle, which are well-established scientific concepts.