Question

Луч свет переходит из воздуха в воду . Угол падения луча равен 30 градусов. Определите угол преломления, если относительный показатель преломления 1.3

Answer 1

Угол падения равен  углу отражения 

sina/sinb=n 

sin30/sinb=1.3

sinb=sin30/1.3~0.38   

sinb~0.38 

b=22 гр 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Answer 2

Calculating the Angle of Refraction

When light passes from one medium to another, the angle of refraction can be calculated using the formula:

\[ \frac{{\sin(\text{{angle of incidence}})}}{{\sin(\text{{angle of refraction}})}} = \frac{{\text{{speed of light in medium 1}}}}{{\text{{speed of light in medium 2}}}} \]

Given: - Angle of incidence = 30 degrees - Relative refractive index = 1.3

We can use the formula to calculate the angle of refraction.

Using the given information, the angle of refraction can be calculated as follows:

\[ \frac{{\sin(30^\circ)}}{{\sin(\text{{angle of refraction}})}} = 1.3 \]

Solving for the angle of refraction:

\[ \sin(\text{{angle of refraction}}) = \frac{{\sin(30^\circ)}}{1.3} = \frac{1}{1.3} \times \sin(30^\circ) = 0.866 \times 0.5 = 0.433 \]

Taking the inverse sine (arcsin) of 0.433 gives the angle of refraction:

\[ \text{{angle of refraction}} \approx \arcsin(0.433) \approx 25.8^\circ \]

The angle of refraction is approximately 25.8 degrees.