Question

Какую работу выполняет электрический ток в электродвигателе за 30 мин , если сила тока в цепи 0,5 А , а напряжение на клеммах двигателя 12 В ?

Answer 1

Дано:

t = 30 мин. = 1800 с.
I = 0,5 A
U = 12 B
________
A - ?

Решение :

А = U×I×t = 1800с×0,5А×12В = 10800 Дж

Answer 2

The question you asked is about the work done by an electric current in an electric motor for 30 minutes, if the current in the circuit is 0.5 A, and the voltage on the motor terminals is 12 V. This is a physics problem that can be solved using the formula:

$$A = I \cdot U \cdot t$$

where $A$ is the work done by the current, $I$ is the current in the circuit, $U$ is the voltage on the motor terminals, and $t$ is the time of the current flow.

To answer your question, we need to plug in the given values into the formula and calculate the result. We also need to make sure that the units are consistent, so we convert 30 minutes to 1800 seconds. Then we get:

$$A = 0.5 \cdot 12 \cdot 1800$$

$$A = 10800 \text{ J}$$

Therefore, the work done by the electric current in the electric motor for 30 minutes is 10800 joules, or 10.8 kilojoules.

This answer is similar to the one given in the first web search result, which is from a website that provides solutions to physics problems from a textbook by Peryshkin. You can check out the link for more details and explanations.