Question

в сосуд с водой имеющей температуру 0 градусов, впустили пар массой 1 кг. при температуре 100 градусов. Сколько воды было в сосуде если через некоторое время температура в нем установится 20 градусов?

Answer 1

Mв-?
tв=0гр
Mп=1кг
tп=100гр
tc=20гр
L=2200КДж/кгж; с= 4200Дж/кг
Qп=Qв - количества теплоты отданное паром = кол-ву теплоты полученному водой\
LMп+сМп(100-20)=сМв(20-0); Мв=(LMп+cМп*100)/20с=Мп(L+100c)/20c
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Answer 2

Calculation of the Amount of Water in the Vessel

To calculate the amount of water in the vessel, we can use the principle of conservation of energy. The heat gained by the water is equal to the heat lost by the steam. We can use the formula:

m1 * c1 * (Tf - Ti) = m2 * c2 * (Tf - Ti)

Where: - m1 is the mass of water - c1 is the specific heat capacity of water - Tf is the final temperature (20 degrees Celsius) - Ti is the initial temperature (0 degrees Celsius) - m2 is the mass of steam - c2 is the specific heat capacity of steam

We are given that the mass of steam is 1 kg and its initial temperature is 100 degrees Celsius. We need to find the mass of water.

Let's substitute the known values into the formula and solve for m1:

1 kg * c2 * (20 - 0) = m1 * c1 * (20 - 0)

Since the specific heat capacity of steam is much smaller than that of water, we can assume that c2 ≈ 0. Therefore, the equation simplifies to:

20 * m1 * c1 = 0

This implies that the mass of water, m1, is 0. Therefore, there is no water in the vessel.

Conclusion

Based on the given information, there is no water in the vessel after the steam is introduced and the temperature stabilizes at 20 degrees Celsius.

Please let me know if you found this information helpful or if you have any further questions!