Question

Струя воды в гидоромотере вылетает из ствола со скоростью 50 м/с под углом 35 градусов. Найти наибольшую высоту подъёма струи.

Answer 1

Вроде, так: h= (50*sin35)^2/2*9,8 = 41,95 м

Answer 2

Finding the Maximum Height of a Water Jet

To find the maximum height of a water jet, we can use the principles of projectile motion. The water jet can be treated as a projectile launched at an angle with an initial velocity of 50 m/s.

The maximum height of the water jet can be determined using the following formula:

H = (V^2 * sin^2θ) / (2 * g)

Where: - H is the maximum height of the water jet - V is the initial velocity of the water jet (50 m/s) - θ is the angle at which the water jet is launched (35 degrees) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Let's calculate the maximum height using the given values:

H = (50^2 * sin^2(35)) / (2 * 9.8)

Calculating this expression gives us the maximum height of the water jet.

Please note that the above formula assumes ideal conditions and neglects air resistance.

Now, let's calculate the maximum height.