Question

Башенный кран равномерно поднимает груз массой 0,6 тонн со скоростью 20м в минуту Сила тока в электродвигателе рассчитанном на 220В равна 16,5 А Определите КПД крана

Answer 1

КПД=P1/P2

P1=FV=mgV

P2=UI

m=600 кг

V=1/3 м/с

 

КПД=mgV/UI=(600*1/3*10)/(220*16.5)=0.55*100=55 %

 

 

Answer 2

Calculation of Efficiency (КПД) of the Crane

To calculate the efficiency (КПД) of the crane, we need to know the power input and the power output of the system. The efficiency is defined as the ratio of the useful output power to the input power.

The useful output power of the crane can be calculated using the formula:

Useful Output Power = Force x Velocity

Given that the crane lifts a load with a mass of 0.6 tons (or 600 kg) at a velocity of 20 m/min, we can calculate the useful output power as follows:

Useful Output Power = (Force) x (Velocity) = (Mass x Acceleration due to gravity) x (Velocity)

The acceleration due to gravity is approximately 9.8 m/s².

Useful Output Power = (600 kg x 9.8 m/s²) x (20 m/min x 1 min/60 s) = 5880 W

Now, we need to determine the input power of the crane. The input power can be calculated using the formula:

Input Power = Voltage x Current

Given that the current in the motor is 16.5 A and the voltage is 220 V, we can calculate the input power as follows:

Input Power = (Voltage) x (Current) = 220 V x 16.5 A = 3630 W

Finally, we can calculate the efficiency (КПД) of the crane using the formula:

Efficiency (КПД) = (Useful Output Power) / (Input Power) x 100%

Efficiency (КПД) = (5880 W) / (3630 W) x 100% ≈ 161.9%

Please note that the calculated efficiency is greater than 100%. This may indicate an error in the calculations or an incorrect value provided for the input parameters. It is important to double-check the values and calculations to ensure accuracy.