Question

Автомобиль движется прямолинейно и равноускоренно и за промежуток времени 40 с проходит путь 800 м. Если модуль скорости автомобиля за это время увеличился в 3 раза то модуль ускорения равен

Answer 1

800 умножить на 40 и все

Answer 2

Given Information:

- The car is moving in a straight line. - The car is moving with constant acceleration. - The car travels a distance of 800 m in a time interval of 40 s. - The magnitude of the car's velocity increases by a factor of 3 during this time interval.

Calculating Acceleration:

To find the magnitude of the acceleration, we can use the equation of motion:

s = ut + (1/2)at^2

where: - s is the distance traveled (800 m), - u is the initial velocity (unknown), - t is the time interval (40 s), - a is the acceleration (unknown).

Since the car is moving with constant acceleration, we can use the equation:

v = u + at

where: - v is the final velocity (3 times the initial velocity).

Rearranging the equation, we get:

u = v - at

Substituting the values, we have:

u = 3u - at

Simplifying, we get:

2u = at

Now, we can substitute the value of u in the equation of motion:

s = (1/2)at^2

Substituting the value of u, we have:

s = (1/2)(2u/t)t^2

Simplifying, we get:

s = ut

Substituting the values of s and t, we have:

800 = ut

Substituting the value of u from the previous equation, we have:

800 = (at/t)t

Simplifying, we get:

800 = at

Now, we can substitute the value of a:

800 = 2ut

Simplifying, we get:

a = 800 / (2t)

Substituting the value of t (40 s), we can calculate the acceleration:

a = 800 / (2 * 40) = 10 m/s^2

Therefore, the magnitude of the acceleration is 10 m/s^2.