Question

Тело объемом 40 см в кубе погрузили в керосин. Чему равна выталкивающая сила, действующая на тело? Плотность керосина 800 кг/м в кубе

Answer 1

Fа=V*pк*g

где
V- объем тела.
рк- плтность керосина.
g- ускорение свободного падения. 

Answer 2

Calculation of the Buoyant Force

To calculate the buoyant force acting on an object submerged in a fluid, we need to consider the density of the fluid and the volume of the object. In this case, the object has a volume of 40 cm³ and is submerged in kerosene with a density of 800 kg/m³.

The buoyant force can be calculated using the formula:

Buoyant force = density of fluid × volume of the object × acceleration due to gravity

Given that the volume of the object is 40 cm³ and the density of kerosene is 800 kg/m³, we need to convert the volume to cubic meters before calculating the buoyant force.

Converting the volume of the object from cubic centimeters (cm³) to cubic meters (m³):

Volume of the object = 40 cm³ = 40 × 10^(-6) m³

Now we can calculate the buoyant force:

Buoyant force = (density of kerosene) × (volume of the object) × (acceleration due to gravity)

Buoyant force = 800 kg/m³ × 40 × 10^(-6) m³ × 9.8 m/s²

Calculating the buoyant force:

Buoyant force = 0.0312 N

Therefore, the buoyant force acting on the object submerged in kerosene is approximately 0.0312 Newtons.

Please note that the above calculation assumes that the object is fully submerged in the kerosene and that the kerosene is incompressible.