Question

Свободно падающий камень пролетел последние ¾ пути за 1 секунду. С какой высоты падал камень?

Answer 1

Тело равноускоренно движущееся проходит за равные интервалы времени пути 1 3 5 7 "отрезков".
Если за секунду тело прошо 3 четвёртых -нам повезло:
-в 1-ю секунду пройдена 1/4 пути
-во вторую 3/4 пути.
Значит полёт длился 2 секунды. Же*Те квадрат /2 равно:
10*2*2/2= 20 метров.
Если Же взять не 10, а 9.81 - можете пересчитать.

Answer 2

Calculation of the Height

To determine the height from which the stone fell, we can use the equation of motion for a freely falling object. The equation is:

h = (1/2) * g * t^2

Where: - h is the height from which the stone fell, - g is the acceleration due to gravity (approximately 9.8 m/s^2), - t is the time it took for the stone to fall.

In this case, we know that the stone fell the last 3/4 of the distance in 1 second. Let's calculate the height using this information.

Calculation

To calculate the height, we need to find the time it took for the stone to fall the last 3/4 of the distance. Since the time is not given directly, we can use the equation of motion for uniformly accelerated motion:

d = (1/2) * a * t^2

Where: - d is the distance traveled, - a is the acceleration, - t is the time.

In this case, the distance traveled is 3/4 of the total distance, and the acceleration is the acceleration due to gravity. Let's calculate the time using this equation.

Using the equation, we have:

(3/4) * h = (1/2) * g * t^2

Simplifying the equation, we get:

h = (2/3) * g * t^2

Now, let's substitute the given values into the equation and solve for h.

Given: - The stone fell the last 3/4 of the distance in 1 second.

Substituting these values into the equation, we have:

h = (2/3) * (9.8 m/s^2) * (1 s)^2

Calculating the equation, we find:

h ≈ 6.53 meters

Therefore, the stone fell from a height of approximately 6.53 meters.

Please note that the above calculation assumes that the stone was dropped from rest and that air resistance is negligible.