Question

Период свободных электромагнитных колебаний в идеальном колебательном контуре Т = 0,2 мс . Определите число полных колебаний за промежуток времени дэльта т = 1с .

Answer 1

N= t/T=1/0,2*10^-3=5000- ответ

Answer 2

Calculation of the Number of Complete Oscillations

To determine the number of complete oscillations in a given time interval, we need to know the period of free electromagnetic oscillations in an ideal oscillatory circuit and the duration of the time interval.

The period of free electromagnetic oscillations in an ideal oscillatory circuit is given as T = 0.2 ms.

The duration of the time interval is given as Δt = 1 s.

To calculate the number of complete oscillations, we can divide the duration of the time interval by the period of oscillation:

Number of complete oscillations = Δt / T

Substituting the given values:

Number of complete oscillations = 1 s / 0.2 ms

Converting the units to match:

Number of complete oscillations = (1 s / 0.2 ms) * (1000 ms / 1 s)

Simplifying the expression:

Number of complete oscillations = 5000

Therefore, there are 5000 complete oscillations in the given time interval of 1 second.

Please note that the calculation assumes ideal conditions and does not take into account any external factors that may affect the oscillations.