Question

Узнайте среднюю орбитальную скорость спутника , если средняя высота его орбиты над Землёй 1200 км. , а период обращения 105 минут . Радиус Земли 6400 км.

Answer 1

1 способ

скорость спутника - это первая космическая скорость:

m a = (G m M)/(R+h)²,

(m v²)/(R+h) = (G m M)/(R+h)²,

v = sqrt((GM)/(R+h)).

масса Земли M ≈ 6*10^(24) кг, радиус Земли R = 64*10^(5) м

v = sqrt((6.67*10^(-11)*6*10^(24))/(64*10^(5)+12*10^(5))) ≈ 7 256.6 м/с

2 способ

v = L / t = 2π(R+h) / T.

v = (2*3.14*(64*10^(5)+12*10^(5)))/6300 ≈ 7575.9 м/с

Answer 2

V=2Pi*(R+H)*N
N=1/6400
v=2*3.14*7600/6400=7.4575 км/с

Answer 3

Calculation of the Average Orbital Speed of a Satellite

To calculate the average orbital speed of a satellite, we can use the formula:

Average Orbital Speed (v) = 2πr / T

Where: - v is the average orbital speed - r is the radius of the satellite's orbit - T is the period of revolution of the satellite

Given the following information: - Radius of the Earth (R) = 6400 km - Average altitude of the satellite's orbit (h) = 1200 km - Period of revolution of the satellite (T) = 105 minutes

To calculate the radius of the satellite's orbit (r), we need to add the altitude of the orbit to the radius of the Earth:

r = R + h

Substituting the given values: r = 6400 km + 1200 km = 7600 km

Now, we can substitute the values of r and T into the formula to calculate the average orbital speed (v):

v = 2πr / T

v = 2π * 7600 km / 105 minutes

Converting the units: - 1 km = 1000 m - 1 minute = 60 seconds

v = 2π * 7600 km * (1000 m/km) / (105 minutes * 60 seconds/minute)

Simplifying the equation: v = 2π * 7600 * 1000 / (105 * 60) m/s

Calculating the value: v ≈ 7.66 km/s

Therefore, the average orbital speed of the satellite is approximately 7.66 km/s.