Question

Над идеальным газом совершена работа А=300 Дж,при этом его внутренняя энергия возросла на дельтаU = 500 Дж. Какое количество теплоты сообщили газу в этом процессе?

Answer 1

∆U=A+Q

Q=∆U-A

Q=500-300=200 (Дж)

Answer 2

Calculation of Heat Transferred to the Gas

To determine the amount of heat transferred to the gas in this process, we need to use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

The equation for the first law of thermodynamics is:

ΔU = Q - W

Where: - ΔU is the change in internal energy of the gas - Q is the heat added to the gas - W is the work done by the gas

In this case, we are given that the change in internal energy (ΔU) is 500 J and the work done (W) is 300 J. We need to find the heat added to the gas (Q).

Plugging in the given values into the equation, we have:

500 J = Q - 300 J

To solve for Q, we can rearrange the equation:

Q = 500 J + 300 J

Calculating the sum:

Q = 800 J

Therefore, the amount of heat transferred to the gas in this process is 800 J.