Question

луч света падает из воздуха на поверхность жидкости под углом 40 и преломляется под углом 24. при каком угле падения луча угол преломления будет 20 градусов

Answer 1

sinA/sin B=sin X/sin B1; sin X=sin A*sin B1/sin B= sin 40*sin 20/sin 24=0.6428*0.3420/0.4067=0.5405 B1=33 градусов приблизительно. Точнее можна если использовать данные за таблицей Брадисса.

Answer 2

Given Information:

A beam of light is incident on the surface of a liquid at an angle of 40 degrees and is refracted at an angle of 24 degrees. The question is asking at what angle of incidence the angle of refraction will be 20 degrees.

Snippet Analysis:

I found a relevant snippet that provides the formula for calculating the angle of refraction. According to the snippet, the formula is as follows:

sin(angle of incidence) / sin(angle of refraction) = refractive index of the medium

Calculation:

To find the angle of incidence at which the angle of refraction is 20 degrees, we can rearrange the formula and solve for the angle of incidence.

sin(angle of incidence) / sin(angle of refraction) = refractive index of the medium

sin(angle of incidence) / sin(20 degrees) = refractive index of the medium

Since the refractive index of the medium is not given, we cannot calculate the exact angle of incidence. We would need the refractive index of the medium to proceed with the calculation.

Conclusion:

Without knowing the refractive index of the medium, we cannot determine the angle of incidence at which the angle of refraction will be 20 degrees.