Question

Орудие установлено на железнодорожной платформе. Масса платформы с орудием 50 т, масса снаряда 25 кг. Орудие выстреливает в горизонтальном направлении вдоль железнодорожного пути. Начальная скорость снаряда 1000 м/с. Какую скорость будет иметь платформа после второго выстрела?

Answer 1

M1=450[кг]m2=5[кг]v2=450[м/с]t=0,2[c]Решениесогласно закуону сохранения импульсаm1v1+m2v2=0v1=(m2v2)/m1ну а путьнайдем из уравнения для пути S=v(начальная)*t-at/2a=-v(начальная)/t (ускорение отрицательно так как v(конечная)=0, пушка остановилась)В нашем случаи v1=v(начальной)тогдаS=v1t-v1t/2соответственноS=v1t/2S=t(m2v2)/2m1S=0,2*5*450/2*450=0,5 [м]

Answer 2

Calculation of the Platform's Velocity after the Second Shot

To determine the velocity of the platform after the second shot, we can use the principle of conservation of momentum. According to this principle, the total momentum before the second shot is equal to the total momentum after the second shot.

The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the momentum of the platform with the gun is equal to the momentum of the projectile.

Let's denote the mass of the platform as m_platform (50,000 kg), the mass of the projectile as m_projectile (25 kg), the initial velocity of the projectile as v_initial (1000 m/s), and the final velocity of the platform after the second shot as v_final.

Using the conservation of momentum, we can write the equation:

m_platform * v_initial = (m_platform + m_projectile) * v_final

Substituting the given values:

50,000 kg * 1000 m/s = (50,000 kg + 25 kg) * v_final

Simplifying the equation:

50,000,000 kg*m/s = 50,025 kg * v_final

Solving for v_final:

v_final = (50,000,000 kg*m/s) / 50,025 kg

Calculating the value:

v_final ≈ 999.50 m/s

Therefore, the platform will have a velocity of approximately 999.50 m/s after the second shot.