Question

Молекула массой 3⋅10−26 кг, летящая со скоростью 750 м/с, ударяется о стенку сосуда под углом 45∘ к нормали и под таким же углом упруго отскакивает от неё без потери скорости. Найти импульс силы, полученной стенкой за время удара.

Answer 1

3*10-26*750*косинус 45

Answer 2

Calculation of the Impulse of the Force

To find the impulse of the force exerted by the wall during the collision, we need to calculate the change in momentum of the molecule. The impulse is defined as the change in momentum of an object and is given by the equation:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

Given: - Mass of the molecule = 3 × 10^(-26) kg - Velocity of the molecule = 750 m/s

To calculate the change in momentum, we need to find the initial and final momenta of the molecule.

Initial Momentum

The initial momentum of the molecule can be calculated using the mass and velocity before the collision.

Initial Momentum = mass × initial velocity

Since the molecule is flying towards the wall at an angle of 45 degrees to the normal, we need to find the component of its velocity along the normal direction.

The component of the velocity along the normal direction can be calculated using trigonometry:

Velocity along normal direction = velocity × cos(angle)

Substituting the given values: - Velocity = 750 m/s - Angle = 45 degrees

Velocity along normal direction = 750 m/s × cos(45 degrees)

Final Momentum

The final momentum of the molecule can be calculated using the mass and velocity after the collision.

Since the molecule rebounds from the wall with the same speed and angle, the final momentum will be the same as the initial momentum.

Change in Momentum

The change in momentum can be calculated by subtracting the initial momentum from the final momentum.

Change in Momentum = Final Momentum - Initial Momentum

Now, let's calculate the impulse of the force exerted by the wall during the collision.

Calculation:

Given: - Mass of the molecule = 3 × 10^(-26) kg - Velocity of the molecule = 750 m/s - Angle of collision = 45 degrees

Velocity along normal direction = 750 m/s × cos(45 degrees)

Initial Momentum = mass × initial velocity

Final Momentum = Initial Momentum

Change in Momentum = Final Momentum - Initial Momentum

Impulse = Change in Momentum

Now, let's substitute the given values and calculate the impulse.

Velocity along normal direction = 750 m/s × cos(45 degrees) = 750 m/s × 0.7071

Initial Momentum = (3 × 10^(-26) kg) × (750 m/s × 0.7071)

Final Momentum = Initial Momentum

Change in Momentum = Final Momentum - Initial Momentum

Impulse = Change in Momentum

Please note that the search result snippet provided does not contain the necessary information to directly answer the question. However, the above explanation provides a step-by-step approach to calculate the impulse of the force exerted by the wall during the collision.