Question

Тепловая машина получает от нагревателя за цикл количество теплоты Q=480 ДЖ. определите работу , совершаемую машиной за цикл , если КПД машины n=20 %

Answer 1

Q=480  n=0.2    A=?

n=A/Q       A=n*Q=0.2*480=96 Дж

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Answer 2

Calculation of Work Done by the Heat Engine

To determine the work done by the heat engine during a cycle, we need to use the formula:

Work (W) = Heat Input (Q) - Heat Output (Q_out)

Given that the heat input (Q) is 480 J and the efficiency (n) of the machine is 20%, we can calculate the heat output (Q_out) using the formula:

Efficiency (n) = (Work (W) / Heat Input (Q)) * 100

Solving for W, we have:

W = (n / 100) * Q

Substituting the given values:

W = (20 / 100) * 480 J

Calculating the work done by the heat engine:

W = 0.2 * 480 J = 96 J

Therefore, the work done by the heat engine during the cycle is 96 J.