
Лифт поднялся с первого на пятый этаж и снова опустился на первый. высота одного етажа 3м. Знайти
модуль перемещения и шлях лифта

Ответы на вопрос

1этаж 3м
Путь на верх 3×4=12м
Умножаем на 4 тк лифт проходит 4 этажа и оказывается на 5ом
Путь вниз 3×4=12
Весь путь
L=12+12=24м
Перемещение S=0м
Ответ 0м ,24м



Calculation of the Elevator's Displacement and Distance Traveled
To calculate the elevator's displacement and distance traveled, we need to consider the elevator's movement from the first floor to the fifth floor and back to the first floor.
Given that the height of each floor is 3 meters, we can calculate the displacement and distance traveled as follows:
1. Displacement: - The displacement of an object is the shortest distance between its initial and final positions. In this case, the initial position is the first floor, and the final position is also the first floor after going up to the fifth floor and coming back down. - Since the elevator returns to its initial position, the displacement is zero. - Therefore, the displacement of the elevator is 0 meters.
2. Distance Traveled: - The distance traveled by the elevator is the total distance covered during its movement from the first floor to the fifth floor and back to the first floor. - To calculate the distance traveled, we need to find the sum of the distances covered during the upward and downward movements. - The distance covered during the upward movement from the first floor to the fifth floor is 4 floors multiplied by the height of each floor (4 * 3 = 12 meters). - The distance covered during the downward movement from the fifth floor back to the first floor is also 4 floors multiplied by the height of each floor (4 * 3 = 12 meters). - Therefore, the distance traveled by the elevator is 24 meters.
In summary, the elevator's displacement is 0 meters, and it travels a distance of 24 meters during its movement from the first floor to the fifth floor and back to the first floor.
Please let me know if you need any further assistance!


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