Question

Стальная деталь объёмом 4 дм³ находится на высоте 2 м. Определите потенцеальную энергию детали

Answer 1

Дано:
сталь ρ=7800кг/м³
V=4дм³ = 4·10⁻³м³
h=2м
Найти:
Ep=?
Решение:
Ep = mgh
m=ρV
m=7800кг/м³×4·10⁻³м³=31,2кг
Ер = 31,2кг×10Н/кг×2м =624Дж
Ответ: Ер =624Дж

Answer 2

Potential Energy Calculation

To calculate the potential energy of the steel detail, we can use the formula:

Potential Energy (PE) = mass × gravitational acceleration × height

Given that the volume of the steel detail is 4 dm³ and it is located at a height of 2 m, we need to convert the volume to mass and then use the above formula to find the potential energy.

First, we need to convert the volume to mass. The density of steel is approximately 7.8 g/cm³. Therefore, the mass of the steel detail can be calculated as follows:

Mass = Volume × Density

Mass = 4 dm³ × 7.8 g/cm³

Mass = 4 × 1000 cm³ × 7.8 g/cm³ (since 1 dm³ = 1000 cm³)

Mass = 31,200 g

Now, we can calculate the potential energy using the formula:

Potential Energy (PE) = mass × gravitational acceleration × height

Potential Energy (PE) = 31,200 g × 9.81 m/s² × 2 m

Potential Energy (PE) ≈ 611,136 J

So, the potential energy of the steel detail is approximately 611,136 joules.