Question

Найти среднюю скорость молекул углекислого газа при 50(градусов)пожалуйста ребята помогите;)

Answer 1

Дано:

t = 50°C

M = 44 * 10⁻³ кг/моль

k = 1.38 * 10⁻²³ Дж/K

Na = 6 * 10⁻²³ моль ⁻¹

Найти:

v

 

 

Средняя квадратичная скорость вычисляется по формуле:

 

v = √(3kT / m₀)

Мы не знаем значения m₀ - массы молекулы углекислого газа, но можем найти её:

 

m₀ = M / Na, Na - число Авогадро

Подставив всё это вместо m₀ в исходное уравнение, получим:

 

v = √(3kTNa / M)

Теперь определимся со значениями величин:

 

молярная масса M углекислого газа равна 44 * 10⁻³ кг/моль

Постоянная Больцмана  k равна 1.38 * 10⁻²³ Дж/К

T = 50 + 273 K =  3.23 * 10² K

Na = 6 * 10²³ моль ⁻¹

Теперь всё подставляем(обязательно в стандартном виде!!):

 

v = √(3 * 1.28 * 10⁻²³ * 3.23 * 10² * 6 * 10²³ / 4.4 * 10⁻²) = √(74.4 * 10² / 4.4 * 10⁻²) = √(17*10⁴) = √17 * 10² = 4.1 * 10² = 410 м/c

 

 

 

 

Answer 2

Finding the Average Speed of Carbon Dioxide Molecules at 50 Degrees Celsius

To find the average speed of carbon dioxide molecules at 50 degrees Celsius, we can refer to the kinetic theory of gases. According to this theory, the average speed of gas molecules is directly proportional to the square root of the temperature and inversely proportional to the square root of the molar mass of the gas.

The formula to calculate the average speed of gas molecules is:

v = sqrt((3 * k * T) / m)

Where: - v is the average speed of the gas molecules - k is the Boltzmann constant (1.38 x 10^-23 J/K) - T is the temperature in Kelvin - m is the molar mass of the gas in kilograms

To convert the temperature from Celsius to Kelvin, we add 273.15 to the Celsius temperature.

Let's calculate the average speed of carbon dioxide molecules at 50 degrees Celsius.

Calculation:

1. Convert the temperature from Celsius to Kelvin: - 50 degrees Celsius + 273.15 = 323.15 Kelvin

2. Determine the molar mass of carbon dioxide (CO2): - The molar mass of carbon (C) is approximately 12.01 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol. - Since carbon dioxide (CO2) has one carbon atom and two oxygen atoms, the molar mass of CO2 is: - (1 * 12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

3. Convert the molar mass from grams to kilograms: - 44.01 g/mol = 0.04401 kg/mol

4. Substitute the values into the formula: - v = sqrt((3 * 1.38 x 10^-23 J/K * 323.15 K) / 0.04401 kg/mol)

5. Calculate the average speed: - v ≈ 502.7 m/s

Therefore, the average speed of carbon dioxide molecules at 50 degrees Celsius is approximately 502.7 m/s.

Please note that this calculation assumes ideal gas behavior and does not take into account other factors such as intermolecular forces or deviations from ideal gas behavior.